Webelif line.strip() == "Structure: {}".format(structures[i+1]): IndexError: list index out of range 据我所知,这是因为对于.txt文件的最后一部分,没有结束结构:因此它不能设置copy=False. 因此,我确实得到了我想要的.txt文件输出,但正如您所知,没有比代码出错更糟糕的了。 WebOct 29, 2024 · find_elements_by_xpath() returns a list of found elements or None if no elements are found. So in this case you need check length of 'card' before getting items from it. E.g.:
python - How to skip index out of range? - Stack Overflow
WebOct 29, 2024 · When your list is empty in python you can not assign value to unassigned index of list. so you have 2 options here: Use append like : list.append (value) make a loop to assign a value to your list before your main for. Like below: i = 0 while ( i < index_you_want): list [i] = 0 ... #here your main code. WebJul 24, 2016 · So, the i th index may no longer exist after certain removals: >>> x = ['a', 'b', 'c', 'd', 'e'] >>> x [4] 'e' >>> x.pop () 'e' >>> x [4] Traceback (most recent call last): File "", line 1, in IndexError: list index out of range. A simpler way to remove duplicate items is to convert your list to a set, which can only contain ... characteristics of dehydrated skin type
python - xpath - IndexError: list index out of range after …
WebAug 3, 2011 · Trying to access words [-1] in an empty array is just as invalid as words [0]. Add a check to see if len (words) == 0. The same logic holds for nextWords which in this code looks like it too could be empty. You can just do if not words: rather than if len (words) == 0: because an empty container is considered false in Python. WebJan 20, 2024 · freeCodeCamp is a donor-supported tax-exempt 501(c)(3) charity organization (United States Federal Tax Identification Number: 82-0779546) Our mission: to help people learn to code for free. WebFeb 11, 2024 · In some cases this line: content=str (soupout [1]) raises an index out of bound, because soupout is an empty list. If you change it to. if len (soupout) == 0: return None. and then remove the None that were returned by changing. res=pool.map (feng,urls) into. res = pool.map (feng,urls) res = [r for r in res if r is not None] harper college psychology